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"Reference return" of PHP functions
From , 3 Years ago, written in PHP, viewed 52 times.
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https://pastebin.vip/view/976abf49
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<?php
/*
** 值传递和引用传递,值传递传递的是值的一个复本,引用传递传递的是值指向的内存地址
*/
// 函数的引用,定义时也要加上 &
function
&
func
(
$a
,
$b
)
{
// 这里为了更直观看到效果,定义一个静态变量
static
$result
=
0
;
$result
+=
$a
+
$b
;
echo
$result
.
'<br />'
;
return
$result
;
}
$a
=
$b
=
10
;
// PHP里这样写函数的引用调用,和调用普通函数没有区别(只是将函数的返回值复制给$c这个变量,$c做任何改变不会影响上面函数中的$result)
// 要记住:PHP里的函数引用定义及调用都要在函数名前加上 &
$c
=
func
(
$a
,
$b
)
;
// 第一次执行func(),其静态变量$result的值变为 20(10+10)
// 改变$c的值,不会对下面一行语句产生影响
$c
=
666
;
// 第二次执行func(),其静态变量$result的值变为 40(20+10+10)
$c
=
func
(
$a
,
$b
)
;
echo
'<hr />'
;
// 这样才是PHP中引用函数的调用方式
$d
=
&
func
(
$a
,
$b
)
;
// 第三次执行func(),其静态变量$result的值变为 40(40+10+10)
$d
=
888
;
// 第四次执行func(),其静态变量$result的值变为 908(888+10+10)
$d
=
func
(
$a
,
$b
)
;
?>
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'; return $result; } $a = $b = 10; // PHP里这样写函数的引用调用,和调用普通函数没有区别(只是将函数的返回值复制给$c这个变量,$c做任何改变不会影响上面函数中的$result) // 要记住:PHP里的函数引用定义及调用都要在函数名前加上 & $c = func($a,$b); // 第一次执行func(),其静态变量$result的值变为 20(10+10) // 改变$c的值,不会对下面一行语句产生影响 $c = 666; // 第二次执行func(),其静态变量$result的值变为 40(20+10+10) $c = func($a,$b); echo '
'; // 这样才是PHP中引用函数的调用方式 $d = &func($a,$b); // 第三次执行func(),其静态变量$result的值变为 40(40+10+10) $d = 888; // 第四次执行func(),其静态变量$result的值变为 908(888+10+10) $d = func($a,$b); ?>
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