Matrix subtraction

From , 5 Years ago, written in Java, viewed 232 times.

        /**
         * 矩阵减法运算。 矩阵A和B可减的条件是矩阵A的行数等于矩阵B的行数，A的列数等于B的列数 c[i][j] = a[i][j] + b[i][j]
         * 
         * @param b
         *            减数
         * @return
         */
        public Matrix sub(Matrix b) {
                if (b == null) {
                        return null;
                }
 
                Matrix c = null;
                double[][] bData = b.getMatrixData();
                if ((this.matrixData.length != bData.length)
                                || (this.matrixData[0].length != bData[0].length)) {
                        System.out.println("两个矩阵的大小不一致，不能完成减法运算");
                        return c;
                }
                // 结果矩阵的数据
                int cRow = this.matrixData.length;
                int cColumn = this.matrixData[0].length;
                double[][] cData = new double[cRow][cColumn];
                for (int i = 0; i < cRow; i++) {
                        for (int j = 0; j < cColumn; j++) {
                                // 两矩阵对应位置的数字做减法
                                cData[i][j] = this.matrixData[i][j] - bData[i][j];
                        }
                }
                c = new Matrix(cData);
                return c;
        }

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Matrix subtraction

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