Function code of encode64 encryption algorithm implemented by JavaScript

From , 2 Years ago, written in JavaScript, viewed 198 times.
URL https://pastebin.vip/view/7c9e9afa
  1. //encode64编解码
  2. (function() {
  3.     var codeChar = "PaAwO65goUf7IK2vi9-xq8cFTEXLCDY1Hd3tV0ryzjbpN_BlnSs4mGRkQWMZJeuh";
  4.     window.encode64 = function(str) {
  5.         var s = "";
  6.         var a = strToBytes(str); //取得字串的字节数组, 数组长度是字串长度的2倍.
  7.         var res = a.length % 3; //3个字节一组进行处理, 余下特殊处理
  8.         var i = 2, v;
  9.         for (; i < a.length; i += 3) {//每3个字节用4个字符表示, 相当于3个字符(实际上是6个字节)用8个字符编码(实际为16个字节), 看起来容量膨胀了很多, 但是在启用压缩的情况下, 这些又被抵消掉了.
  10.             v = a[i - 2] + (a[i - 1] << 8) + (a[i] << 16);
  11.             s += codeChar.charAt(v & 0x3f);
  12.             s += codeChar.charAt((v >> 6) & 0x3f);
  13.             s += codeChar.charAt((v >> 12) & 0x3f);
  14.             s += codeChar.charAt((v >> 18));
  15.         }
  16.         if (res == 1) {//字节余一位时候, 补2个字符, 64*64>256
  17.             v = a[i - 2];
  18.             s += codeChar.charAt(v & 0x3f);
  19.             s += codeChar.charAt((v >> 6) & 0x3f);
  20.         } else if (res == 2) {//字节余2位的时候, 补3个字节, 64*64*64>256*256, 所以是可行的.
  21.             v = a[i - 2] + (a[i - 1] << 8);
  22.             s += codeChar.charAt(v & 0x3f);
  23.             s += codeChar.charAt((v >> 6) & 0x3f);
  24.             s += codeChar.charAt((v >> 12) & 0x3f);
  25.         }
  26.         return s;
  27.     };
  28.     window.decode64 = function(codeStr) {
  29.         var dic = [];
  30.         for (var i = 0; i < codeChar.length; i++) {
  31.             dic[codeChar.charAt(i)] = i;
  32.         }
  33.         var code = [];
  34.         var res = codeStr.length % 4;
  35.         var i = 3, v;
  36.         for (; i < codeStr.length; i += 4) {
  37.             v = dic[codeStr.charAt(i - 3)];
  38.             v += dic[codeStr.charAt(i - 2)] << 6;
  39.             v += dic[codeStr.charAt(i - 1)] << 12;
  40.             v += dic[codeStr.charAt(i)] << 18;
  41.             code.push(v & 0xff, (v >> 8) & 0xff, (v >> 16) & 0xff);
  42.         }
  43.         if (res == 2) {//正确的字节数肯定是余2或3, 没有1的情况, 如果出现, 舍弃.
  44.             v = dic[codeStr.charAt(i - 3)];
  45.             v += dic[codeStr.charAt(i - 2)] << 6;
  46.             code.push(v & 0xff);
  47.         } else if (res == 3) {
  48.             v = dic[codeStr.charAt(i - 3)];
  49.             v += dic[codeStr.charAt(i - 2)] << 6;
  50.             v += dic[codeStr.charAt(i - 1)] << 12;
  51.             code.push(v & 0xff, (v >> 8) & 0xff);
  52.         }
  53.         return strFromBytes(code);
  54.     };
  55. })();
  56. //javascript/6739

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