Brute force crack Caesar password C source code

From Soft Mockingjay, 1 Year ago, written in C, viewed 186 times.

#include <stdio.h>
#include <string.h>
int main(void)
{
char str[] = "ESP BFTNV MCZHY QZI UFXAD ZGPC ESP WLKJ OZR ZQ NLPDLC LYO JZFC FYTBFP DZWFETZY TD TNSONDLMLOOL";
//对整个字符串循环，把1-25全部尝试一遍，i即为密钥
for(int i = 1; i < 26; i++)
{
//遍历字符串中的每个字符
for(int j = 0; j < strlen(str); j++)
{
if(str[j] == ' ') //如果j是空格，就将j原封不动地打印出来，因为我们需要划分单词
{
printf("%c", str[j]);
}
else //如果不是空格，就将当前字符向后移动i位，i为当前轮的密钥
{
printf("%c", (str[j] + i - 'A') % 26 + 'A'); //打印得到向后移动的密文
}
}
printf("\n\n");
}
return 0;
}
 
 
 
 
凯撒密码为移位密码，手工破解一般是将两位字母替换成is it be on me等单次，  三位字符替换成the等字符，出现最多的字符一般是e。
 
如果是如下字符 rjjy rj ts ymj xfggfym bj bnqq inxhzxxymj uqfs
 
穷举之后，最有可能的一句话是：  MEET ME ON THE SABBATH WE WILL DISCUSSTHE PLAN ，其中  DISCUSSTHE  应该为 DISCUSS   THE

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Brute force crack Caesar password C source code

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