C arbitrary binary conversion

From , 5 Years ago, written in C, viewed 134 times.

/*语法：conversion(char s1[],char s2[],long d1,long d2);
 *参数：
 *s[]：        原进制数字，用字符串表示
 *s2[]：       转换结果，用字符串表示
 *d1： 原进制数
 *d2： 需要转换到的进制数
 *返回值：  null
 *注意：高于9的位数用大写'A'～'Z'表示，2～16位进制通过验证
 */
 
void conversion ( char s[],char s2[],long d1,long d2 )
{
        long i,j,t,num;
        char c;
        num=0;
        for ( i=0; s[i]!='\0'; i++ )
        {
                if ( s[i]<='9'&&s[i]>='0' ) t=s[i]-'0';
                else t=s[i]-'A'+10;
                num=num*d1+t;
        }
        i=0;
        while ( 1 )
        {
                t=num%d2;
                if ( t<=9 ) s2[i]=t+'0';
                else s2[i]=t+'A'-10;
                num/=d2;
                if ( num==0 ) break;
                i++;
        }
        for ( j=0; j<i/2; j++ )
                {c=s2[j]; s2[j]=s[i-j]; s2[i-j]=c;}
        s2[i+1]='\0';
}
 

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C arbitrary binary conversion

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